isNative

_.isNative(value)

检查 value 是否是原始原生函数。

¥Checks if value is a pristine native function.

注意：此方法无法在存在 core-js 包的情况下可靠地检测原生函数，因为 core-js 会绕过这种检测。尽管多次请求，但 core-js 维护者已经明确表示：任何修复检测的尝试都将受到阻碍。因此，我们别无选择，只能抛出错误。不幸的是，这也会影响依赖 core-js 的包，例如 babel-polyfill。

¥Note: This method can't reliably detect native functions in the presence of the core-js package because core-js circumvents this kind of detection. Despite multiple requests, the core-js maintainer has made it clear: any attempt to fix the detection will be obstructed. As a result, we're left with little choice but to throw an error. Unfortunately, this also affects packages, like babel-polyfill, which rely on core-js.

新增于

¥Since

3.0.0

参数

¥Arguments

1. value (*):要检查的值。

   ¥value ()*: The value to check.

返回

¥Returns

(布尔)：如果 value 是原生函数，则返回 true，否则返回 false。

¥(boolean): Returns true if value is a native function, else false.

示例

¥Example

_.isNative(Array.prototype.push);
// => true

_.isNative(_);
// => false